I really need help with a kinematic question

A ball thrown vertically upward at 29.4m/s returns to the ground 6.0s later.
a) how many seconds did the ball take to reach its highest point?
b) How high did the ball go?
c)with what vilocity did it hit the ground?

A ball thrown vertically upward at 29.4m/s returns to the ground 6.0s later.

a) How many seconds did the ball take to reach its highest point?
Since the ball follows a parabolic flight path, it takes just as long to go up as it does to come down. That means 1/2 the tavel time is spent going up to the highest point, or 3 seconds.

b) How high did the ball go?
This on requires some math:
Let a = acceleration due to gravity (9.8 m/s^2), v = initial velocity (29.4 m/s), t = time to top (3 sec)
height = -1/2(a)(t)^2 + (v)(t)
height = -1/2(9.8)(3)^2 + 29.4(3) = 44.1 meters

c) With what velocity did it hit the ground?
Once again, because the flight path is a parabola, the ball decelerates to zero velocity at its peak, then accelerates to attain the same velocity it left with only in the opposite direction or 29.4 m/s.

a) t = T/2 = 6/2 = 3sec
b) H = V²/2g = 44.1 m
c) V2 = Vi = 29.4 m/s downward