Please show work so I can learn how you did it. Yes, I will reward full points.
in a particular television tube, the beam current is 60.0 μA. how long does it take for 3.75 x 10^14 electrons to strike the screen?
The answer is 1.00 s
in a particular television tube, the beam current is 60.0 μA. how long does it take for 3.75 x 10^14 electrons to strike the screen?
The answer is 1.00 s
-
The current I is charge Q transfered divided by the time t taken to transfer that charge, or:
I = Q/t
... so t = Q/I. You are given both Q and I, but Q is in electron charge units (3.75^10^14 e-) and I is in microamperes (aka microcoulombs per second). Convert Q to microcoulombs and then divide to get t in seconds.
1 C = 6.24 x 10^18 e-
1 μC = 6.24 x 10^12 e-
Q = 3.75 x 10^14 e- = (3.75 x 10^14 e-)[1 μC / 6.24 x 10^12 e-]
Q = 60.1 μC
Now the units are compatible. Solve
t = Q/I = 60.1 μC / 60.0 μA = 1.00 s
I = Q/t
... so t = Q/I. You are given both Q and I, but Q is in electron charge units (3.75^10^14 e-) and I is in microamperes (aka microcoulombs per second). Convert Q to microcoulombs and then divide to get t in seconds.
1 C = 6.24 x 10^18 e-
1 μC = 6.24 x 10^12 e-
Q = 3.75 x 10^14 e- = (3.75 x 10^14 e-)[1 μC / 6.24 x 10^12 e-]
Q = 60.1 μC
Now the units are compatible. Solve
t = Q/I = 60.1 μC / 60.0 μA = 1.00 s
-
An amp is 6.24*10^18 electrons per second.
60.0 µA is 6*10^-5 amp.
6.24*10^18 times 6*10^-5 equals 3.744*10^-14
60.0 µA is 6*10^-5 amp.
6.24*10^18 times 6*10^-5 equals 3.744*10^-14