A 1.1 cue ball moving at 0.40m/s at 0.0 degrees runs into the 0.95kg eight ball. After the collision,

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A 1.1 cue ball moving at 0.40m/s at 0.0 degrees runs into the 0.95kg eight ball. After the collision,

[From: ] [author: ] [Date: 12-01-09] [Hit: ]

gets: v3= 0.5458m/s v4=0.......

the cue ball is moving at an angle of -29degrees and the eight ball at 53 degrees. Calculate the velocity of each ball.

How can I solve this?? please help!

-

use the conservation of momentum.
m1v1+m2v2=m1v3+m2v4
1.1*0.4=1.1*v3+0.95*v4 [1]
and the sum of vertical moment is zero!
(v3*sin-29)*1.1=(v4*sin 53)*0.95 [2]
solve [1] and [2] simultaneously.
gets: v3= 0.5458m/s v4=0.58m/s

1

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