A worker on the roof of a house drops his 0.74 kg hammer, which slides down the roof at constant speed of 4.93m/s. The roof makes an angle of 20 with the horizontal, and its lowest point is 21.8 m from the ground. What is the horizontal distance traveled by the hammer from the time it leaves the roof to the time it hits the ground? The acceleration due to gravity is 9.8 m/s2 .Answer in units of m
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Vx = V*cosΘ = 4.93*cos20° = 4.633 m/s
Time to fall t = √[2y/g] = √[2*21.8/9.8] = 2.109 sec
X = Vx*t = 9.77 m
Time to fall t = √[2y/g] = √[2*21.8/9.8] = 2.109 sec
X = Vx*t = 9.77 m