Can someone please help with these two questions
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Can someone please help with these two questions

[From: ] [author: ] [Date: 11-12-25] [Hit: ]
The equilibrium shifts to the right and more porducts are formed.C. No change in equilibrium occurs. The amounts of reactants and products remain the same.D. It is not possible to tell from the information given.......
What happens to the reaction C2H6 + 137kJ C2H4 + H2 when the temperature of the reaction is increased?

A. The equilibrium shifts to the left and more reactants are formed.
B. The equilibrium shifts to the right and more porducts are formed. <----- (my answer)
C. No change in equilibrium occurs. The amounts of reactants and products remain the same.
D. It is not possible to tell from the information given.

When the ionic compound KI is dissolved in water, the I– ions are pulled into solution by the attraction between

A. the K+ and I– ions. <----- (my answer)
B. the K+ ion and the negative end of a water molecule.
C. the I– ion and the negative end of a water molecule.
D. the I– ion and the positive end of a water molecule.

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1. B
Yes, the kJ of energy will increase as temperature is increased, and the equilibrium will shift to the right to accommodate this change. When the equilibrium shifts to right, the products are favored.

2.D
I-ions are negatively charged, and for this, they are attracted to positively charged molecules (like the positive ends of a water molecules). This animation illustrates this idea with NaCl (an ionic compound) and water: http://www.northland.cc.mn.us/biology/bi…

If the K and I ions were more attracted to each other than to H2O, KI would not dissolve in water.

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B This is an endothermic reaction. Hear is required.

D You are asking about the I- ions only.
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