An object accelerates uniformly from the rest to a velocity of 20 m/s in 5s. It then immediately begins to decelerate and comes to full stop after 2s.
a.Calculate the objects acceleration
b.Calculate the objects deceleration
c.Calculate the total distance the object traveled.
a.Calculate the objects acceleration
b.Calculate the objects deceleration
c.Calculate the total distance the object traveled.
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An object accelerates uniformly from the rest to a velocity of 20 m/s in 5s. It then immediately begins to decelerate and comes to full stop after 2s.
Acceleration = (Final velocity – Initial velocity) ÷ time
a.Calculate the objects acceleration = 4 m/s^2
vf = 0
vi = 20
Acceleration = (20 – 0) ÷ 5 = 4 m/s^2
b.Calculate the objects deceleration = 10 m/s^2
vf = 0
vi = 20
Acceleration = (0 – 20) ÷ 2 = -10 m/s^2
The answer is negative, because deceleration is the opposite of acceleration.
c.Calculate the total distance the object traveled.
D = vi * t + ½ * a * t^2
Distance during acceleration = (0 * 5) + (½ * 4 * 5^2) = 50 m
Distance during deceleration = (20 * 2) + (½ * -10 * 2^2) = 40 – 20 = 20 m
Total distance = 70 m
Acceleration = (Final velocity – Initial velocity) ÷ time
a.Calculate the objects acceleration = 4 m/s^2
vf = 0
vi = 20
Acceleration = (20 – 0) ÷ 5 = 4 m/s^2
b.Calculate the objects deceleration = 10 m/s^2
vf = 0
vi = 20
Acceleration = (0 – 20) ÷ 2 = -10 m/s^2
The answer is negative, because deceleration is the opposite of acceleration.
c.Calculate the total distance the object traveled.
D = vi * t + ½ * a * t^2
Distance during acceleration = (0 * 5) + (½ * 4 * 5^2) = 50 m
Distance during deceleration = (20 * 2) + (½ * -10 * 2^2) = 40 – 20 = 20 m
Total distance = 70 m