How large a force F is needed to stop the brick

[From: ] [author: ] [Date: 11-12-02] [Hit: ]

0)/(7.0*10^-4) = 1.714*10^4 N or 1.7*10^4 N-This is question from work power & Energy , In order to solve this question you must have good command over basics .I know that have the answer to this question .......

A 2.0 kg brick is moving at a speed of 6.0 m/s. How large a force F is needed to stop the brick in a time of 7.0 x 10-4s?
Pls help me with details, I need it fofuture how to do
Thank you in advance
the answer must be -1.7x10^4N

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Force = rate of change of momentum = (2.0*6.0)/(7.0*10^-4) = 1.714*10^4 N or 1.7*10^4 N

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This is question from work power & Energy , In order to solve this question you must have good command over basics .I know that have the answer to this question . You can refer this website to know the tricks and formulae to solve this question

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