How many positive four-digit integershave 1 as their first digit and 2 or 5 ....

hi can some1 plz explain dis Q 2 me :D
How many positive four-digit integers have 1 as their first digit and 2 or 5 as their last digit?
(A) 144
(B) 180
(C) 200
(D) 300
(E) 720

4-digit integers with the form of 1xx2 or 1xx5
2nd digit has 10 choices (0-9)
3rd digit has 10 choices 0-9
4th digit has 2 choices
so 10x10x2 = 200
the answer is (C)

It is basically the numbers from zero to ninety nine,
(a) with a one in front and two at the end
(b) with a one in front and five at the end

ie two lots of a hundred.

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