CHEMISTRY HELP NOWWWW!!!! please:)

when copper(II) nitrate reacts with sodium hydroxide, copper (II) hydroxide is produced. How many grams of Cu(OH)2 can be prepared from 12.7g of Cu(NO3)2 and excess NaOH? PLEASE HELP!!!

Cu(NO3)2 + 2 NaOH --> Cu(OH)2 + 2 NaNO3
Moles of Cu(NO3)2 = 12.7 g / 187.5 = 0.0677 moles.
The ratio is 1 to 1 .
Moles of Cu(OH)2 = 0.0677 Grams = 0.0677 x 97.5 = 6.60 g.