a 52-N sled is pulled across a cement sidewalk at constant speed. A horizontal force of 36-N is exerted. What is the coefficient of sliding friction between the sidewalk and the metal runners of the sled?
A rubber ball weighs 49-N
a) what is the mass of the ball?
b) what is the acceleration of the ball if an upward force of 69-N is applied?
thanks!
A rubber ball weighs 49-N
a) what is the mass of the ball?
b) what is the acceleration of the ball if an upward force of 69-N is applied?
thanks!
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Coefficient of friction is simply a ratio of weight to force needed to for it to slide. so just divide you horizontal force by your weight. 36/52 and that's your answer.
Rubber ball question.
A(Smart-*** Answer). It depends on the gravitational pull of the body(planet or moon) your on because a ball of any mass would have different weight on different planets.
A(If you assume the ball is on Earth) 9.8N =1 Kg so divide 49 by 9.8 to get mass Kg which are the proper unit for mass.
B Use th equation F=MA like normal except remember that you have an opposing force of 49 N due to the balls weight so to get net force you subtract 49 from 69 to get 20. so F=20 M= the answer from part A. now use your algebra skills to solve for A. If you have any questions just fav
Rubber ball question.
A(Smart-*** Answer). It depends on the gravitational pull of the body(planet or moon) your on because a ball of any mass would have different weight on different planets.
A(If you assume the ball is on Earth) 9.8N =1 Kg so divide 49 by 9.8 to get mass Kg which are the proper unit for mass.
B Use th equation F=MA like normal except remember that you have an opposing force of 49 N due to the balls weight so to get net force you subtract 49 from 69 to get 20. so F=20 M= the answer from part A. now use your algebra skills to solve for A. If you have any questions just fav