EASY PHYSICS QUESTION!! PLEASE HELP
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EASY PHYSICS QUESTION!! PLEASE HELP

[From: ] [author: ] [Date: 11-11-04] [Hit: ]
which is 7.58 m long. The bullet leaves the barrel with a velocity of 734 m/s. Calculate the acceleration of the bullet.-Vf^2 = Vi^2 + 2 ad.Vf = Vi + (7.......
A racing car traveling initially at 5.29 m/s accelerates uniformly at 7.95 m/s2 for 2.14 s. How far does it travel in this time?


A gun is fired and the bullet is accelerated in the gun barrel, which is 7.58 m long. The bullet leaves the barrel with a velocity of 734 m/s. Calculate the acceleration of the bullet.

-
Vf^2 = Vi^2 + 2 ad.
Vf = Vi + (7.95 x 2.14), = 22.303m/sec.
22.303^2 = 5.29^2 + 2ad.
2ad = (22.303^2 - 5.29^2), = 469.4397.
ad = (469.4397/2), = 234.71985.
d = (234.71985/7.95), = 29.52 metres.

Acceleration = (v^2/2d), = 35,538m/sec^2.
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