Calculate RPM with acceleration and radius
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Calculate RPM with acceleration and radius

[From: ] [author: ] [Date: 11-10-02] [Hit: ]
22x10^6m/s/s x 0.085m] = 322.each rotation involves a circumferential distance of 2 pi r = 0.so this requires 322.7 m/s / 0.53m/rev = 604.......
How fast (in rpm ) must a centrifuge rotate if a particle 8.50cm from the axis of rotation is to experience an acceleration of 125,000g's?

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centrip accel = v^2/r

1 g = 9.8m/s/s so this acceleration = 1.22x10^6m/s/s

so we want v^2/r = 1.22x10^6m/s/s

r=0.085m,

v=sqrt[1.22x10^6m/s/s x 0.085m] = 322.7m/s

each rotation involves a circumferential distance of 2 pi r = 0.53m

so this requires 322.7 m/s / 0.53m/rev = 604.5rev/s or 36270 rpm
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