How fast (in rpm ) must a centrifuge rotate if a particle 8.50cm from the axis of rotation is to experience an acceleration of 125,000g's?
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centrip accel = v^2/r
1 g = 9.8m/s/s so this acceleration = 1.22x10^6m/s/s
so we want v^2/r = 1.22x10^6m/s/s
r=0.085m,
v=sqrt[1.22x10^6m/s/s x 0.085m] = 322.7m/s
each rotation involves a circumferential distance of 2 pi r = 0.53m
so this requires 322.7 m/s / 0.53m/rev = 604.5rev/s or 36270 rpm
1 g = 9.8m/s/s so this acceleration = 1.22x10^6m/s/s
so we want v^2/r = 1.22x10^6m/s/s
r=0.085m,
v=sqrt[1.22x10^6m/s/s x 0.085m] = 322.7m/s
each rotation involves a circumferential distance of 2 pi r = 0.53m
so this requires 322.7 m/s / 0.53m/rev = 604.5rev/s or 36270 rpm