How do you calculate speed given the acceleration of 4.5 x 10-3m/s2 and a time of 18 mins?
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From (See sources below)
Formula: v = v0 + at
Where: v = velocity (speed), v0 = initial velocity, a = acceleration, t = time
Since initial velocity wasn't given we'll make it zero essentially ignoring it. This will then give us v = at.
Since acceleration is given in seconds we'll convert the 18 min to seconds: 18 min * 60 sec / 1 min = 1080 sec.
So (for easiness) v = 0.0045 m/s2 * 1080 s
s cancels with s2 to give s so v = 0.0045 * 1080 m/s
You should be able to answer the rest.
Formula: v = v0 + at
Where: v = velocity (speed), v0 = initial velocity, a = acceleration, t = time
Since initial velocity wasn't given we'll make it zero essentially ignoring it. This will then give us v = at.
Since acceleration is given in seconds we'll convert the 18 min to seconds: 18 min * 60 sec / 1 min = 1080 sec.
So (for easiness) v = 0.0045 m/s2 * 1080 s
s cancels with s2 to give s so v = 0.0045 * 1080 m/s
You should be able to answer the rest.
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a = v/t
at=v
you need to convert minutes to seconds 18mins = 1080s
(4.5*10^-3 m/s^2) * (1080s) = 4.86m/s
at=v
you need to convert minutes to seconds 18mins = 1080s
(4.5*10^-3 m/s^2) * (1080s) = 4.86m/s