How to add and subtract vectors (with image)
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How to add and subtract vectors (with image)

[From: ] [author: ] [Date: 11-08-29] [Hit: ]
keeping track of sign.Then add the components upAx + Bx = Resultant x (Rx)Ay + By = RyThen:Rx^2 + Bx^2 = R^2Angle of R = tan^-1 Ry/RxExample:A:75 units @ 110 degreesB: 125 units @ 285 degreesA is in the 2nd quadrent 110 degrees counter clockwise from the + x axis ===> it is (180 - 110 from the - x axis or 70 degreesclockwise from the - x axis.Because it is in the 2nd quadrent the x component will be negative and the y component will be positive. ===>We do the trig for a 20 - 70 - 90 triangle.......

x-axis component = the magnitude of the vector multiplied by sin 30
Bx = 15 sin 30
y-axis component = the magnitude of the vector multiplied by cos 30
By = 15 cos 30

***pay attention to whether the given angle is opposite or adjacent, because this will also give the equivalent answer:***

Bx = 15 cos 60
By = 15 sin 60

I generally always calculate the angle from the positive x-axis and use that, because I know that the cosine of that angle will always give me the x component of the vector without possibly making mistakes in whether to use sine or cosine, and it will also automatically give me the correct sign for the vector component.

x-axis component of vector B = 7.5
y-axis component of vector B = 13

I'm going to give an example of adding 2 random vectors, when you figure out the components of each vector it's easy to use this formula. Basically you add the x-components of each vector together and that sum is the x-component of the resultant vector, and same for the y-components. The formula is this:

+ =
So for example if we had 2 vectors <2, 1> and <-4, 3> the sum of those two vectors would be <-2, 4>

Subtraction is the same process:

To find the direction of a vector take the inverse tangent of the y-component divided by the x-component, or arctan (y/x). The magnitude of any vector is given by sqrt(a^2 + b^2).

-
Do the trig and break the vectors into components. keeping track of sign. Then add the components up

Ax + Bx = Resultant x (Rx)

Ay + By = Ry

Then:

Rx^2 + Bx^2 = R^2

Angle of R = tan^-1 Ry/Rx

Example:

A: 75 units @ 110 degrees

B: 125 units @ 285 degrees

A is in the 2nd quadrent 110 degrees counter clockwise from the + x axis ===> it is (180 - 110 from the - x axis or 70 degrees clockwise from the - x axis. Because it is in the 2nd quadrent the x component will be negative and the y component will be positive. ===> We do the trig for a 20 - 70 - 90 triangle. Hypotenuse is 75 units
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