Velocity, v=u+at where u= initial velocity=0 as fallen freely, a= acceleration due to gravity, t=15s
v=0+9.81*15
=147.15 m/s
Momentum = mass*velocity = 3.4*147.15 =500 kg-m/s
v=0+9.81*15
=147.15 m/s
Momentum = mass*velocity = 3.4*147.15 =500 kg-m/s
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First, find the velocity of the object after it has fallen.
Using v = v₀ + at, we see that the velocity of the ball after 15 seconds is:
v = 0.0 m/s + (-9.8 m/s^2)(15 s) = -147 m/s.
(This is neglecting air friction.)
Since p = mv, the momentum of the object is:
p = mv
= (3.4 kg)(-147 m/s)
= -540 kg*m/s, to 2 s.f.
I hope this helps!
Using v = v₀ + at, we see that the velocity of the ball after 15 seconds is:
v = 0.0 m/s + (-9.8 m/s^2)(15 s) = -147 m/s.
(This is neglecting air friction.)
Since p = mv, the momentum of the object is:
p = mv
= (3.4 kg)(-147 m/s)
= -540 kg*m/s, to 2 s.f.
I hope this helps!
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If its fallin downwards then
F = 3.4 * 9.8 =
t = 15s
Impulse = F.t
impulse = change in momentum
F.t = 0 - p its falling from rest
p = F.t
F = 3.4 * 9.8 =
t = 15s
Impulse = F.t
impulse = change in momentum
F.t = 0 - p its falling from rest
p = F.t