Physics Electric Potential Help
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Physics Electric Potential Help

[From: ] [author: ] [Date: 11-05-22] [Hit: ]
=>2 x 9.6 x 10^-19 = 1/2 x 9.=>v = √[4.=>v = 2.......
An electron is placed midway between two parallel conducting plates that are spaced 3.0 mm apart. The plates are attached to the terminals of a 12.0 V battery.

a) What is the direction and magnitude of the electric field?

b) How much work would be done by moving the electron from the midpoint to the surface of the (-) plate?

c) If the electron were released from a point midway between the plates, what would be its velocity when it struck the (+) plate?

d) If the potential were doubled, how much faster would the velocity be?


Any help would be greatly appreciated. Easy 10 points for a decent explanation.

-
(a) By E = V/d = 12/(3 x 10^-3) = 4000 V/m or N/C
(b) By W = Fd
=>W = (eE) x d
=>W = 1.6 x 10^-19 x 4000 x 1.5 x 10^-3
=>W = 9.6 x 10^-19 J
(c) By the work energy relation:-
=>W = ∆KE
=>9.6 x 10^-19 = 1/2 x 9.1 x 10^-31 x v^2
=>v = √[2.11 x 10^12]
=>v = 1.45 x 10^6 m/s
(d) By the work energy relation:-
=>W = ∆KE
=>2 x 9.6 x 10^-19 = 1/2 x 9.1 x 10^-31 x v^2
=>v = √[4.22 x 10^12]
=>v = 2.05 x 10^6 m/s
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