A diver then jumps into the ocean and, after a short time treading water on the ocean surface, checks the tank's pressure and finds that it is only 221 atm. Assuming the diver has inhaled a negligible amount of air from the tank, what is the temperature of the ocean water?
Thanks!!
Thanks!!
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This is a job for Amontons' Law.
P1/T1 = P2/T2
Let T2 be the ocean temperature. Isolating T2 in the formula:
P1T2 = P2T1
T2 = P2T1/P1
T2 = (221 atm)(303 K) / 231 atm
T2 = 289.88 K or 16.88°C (Answer)
Have a good day.
P1/T1 = P2/T2
Let T2 be the ocean temperature. Isolating T2 in the formula:
P1T2 = P2T1
T2 = P2T1/P1
T2 = (221 atm)(303 K) / 231 atm
T2 = 289.88 K or 16.88°C (Answer)
Have a good day.