A 4 kilogram block of ice is removed from a freezer where its temperature was maintained at – 20 degrees Celsius. How much heat does the ice absorb as it is warmed to – 10 degrees? (The specific heat capacity of ice is 2,000 joules per kilogram degree Celsius.)
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Q = m*c*ΔT = 4kg*2000J/kg-oC*(-10 --20) = 80000J