If an object is half the focal length f
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If an object is half the focal length f

[From: ] [author: ] [Date: 11-04-22] [Hit: ]
Subtract 2/f from both sides, you find 1/i = -1/f. Solving for i gives you i= --f. Its a virtual image and appears *behind* the mirror at a distance equal to the focal length. Boom. Done.......
away from a concave mirror, where will the image be located with respect to f?

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The equation is 1/o + 1/i = 1/f

For a concave mirror, f is positive. The object distance is 1/(.5f) which is equal to 2/f. Subtract 2/f from both sides, you find 1/i = -1/f. Solving for i gives you i= --f. It's a virtual image and appears *behind* the mirror at a distance equal to the focal length. Boom. Done.
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