i have been stuck on this question for a while :/
-A committee of 5 is to be chosen from 7 women and 6 men. in how many ways could this be done if:
a) a man and his wife must be on the committee?
d) the committee must be predominantly women?
THANKS SO MMUCH!!
-A committee of 5 is to be chosen from 7 women and 6 men. in how many ways could this be done if:
a) a man and his wife must be on the committee?
d) the committee must be predominantly women?
THANKS SO MMUCH!!
-
a)You need to know the number of wives amongst the 7 ladies.
b) There must be at least 3 women
so 3W and 2 M , choices 7C3X6C2=35X15=525
4W and 1 M , choices 7C4X6C1=35X6 =210
5W and 0M, choices 7C5=21 so altogether 756
b) There must be at least 3 women
so 3W and 2 M , choices 7C3X6C2=35X15=525
4W and 1 M , choices 7C4X6C1=35X6 =210
5W and 0M, choices 7C5=21 so altogether 756