A fair 6-sided die is tossed six times. What is the probability of tossing exactly two 5s?
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the two 5s could have 6c2 = 15 spots in which they could occur in a sequence of 6 tosses, and the Pr of any such sequence (eg 5x5xxx) has a Pr of (1/6)^2*(5/6)^4, so indicated Pr = 15*5^4/6^6 = 0.2009 <----
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0.20094
Go to this website: http://keisan.casio.com/exec/system/1223626305
Put "6" for number of trials, leave probability of success at "1/6", and look for "2" under "success times".
Go to this website: http://keisan.casio.com/exec/system/1223626305
Put "6" for number of trials, leave probability of success at "1/6", and look for "2" under "success times".
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P(5) = 1/6
(1/6)^2 X (5/6)^4
.0134
(1/6)^2 X (5/6)^4
.0134