CAN YOU SOLVE FOR N (so that the expression is a perfect square tri.) AND FACTOR ?? please and thankyou.
1) c^(2)+6c+n
2) x^(2)-18x+n
3) x^(2)-7x+n
5) c^(2)-2/5c+n
6) x^(2)+2/5x+n
1) c^(2)+6c+n
2) x^(2)-18x+n
3) x^(2)-7x+n
5) c^(2)-2/5c+n
6) x^(2)+2/5x+n
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1) c^(2)+6c+n
take 1/2 of 6 to get 3. square this and get n = 9
c^2 + 6c + 9 = (c+3)^2
2) x^(2)-18x+n
take 1/2 of -18 to get -9. square this and get n = 81
x^2 -18x +81 = (x - 9)^2
3) x^(2)-7x+n
take 1/2 of -7 to get -7/2. square this and get n = 49/4
x^2 - 7x + 49/4 = (x - 7/2)^2
5) c^(2)-2/5c+n
take 1/2 of -2/5 to get -1/5. square this and get n = 1/25
c^2 - (2/5)c + 1/25 = (x - 1/5)^2
6) x^(2)+2/5x+n
take 1/2 of 2/5 to get 1/5. square this and get n = 1/25
x^2 + (2/5)x + 1/25 = (x + 1/5)^2
take 1/2 of 6 to get 3. square this and get n = 9
c^2 + 6c + 9 = (c+3)^2
2) x^(2)-18x+n
take 1/2 of -18 to get -9. square this and get n = 81
x^2 -18x +81 = (x - 9)^2
3) x^(2)-7x+n
take 1/2 of -7 to get -7/2. square this and get n = 49/4
x^2 - 7x + 49/4 = (x - 7/2)^2
5) c^(2)-2/5c+n
take 1/2 of -2/5 to get -1/5. square this and get n = 1/25
c^2 - (2/5)c + 1/25 = (x - 1/5)^2
6) x^(2)+2/5x+n
take 1/2 of 2/5 to get 1/5. square this and get n = 1/25
x^2 + (2/5)x + 1/25 = (x + 1/5)^2