I need help finding the derivative of this so any help would be great...thanks a lot :))
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f(x) = (2x³ - 1) / x²
u = 2x³ - 1
u' = 6x²
v = x²
v' = 2x
d(u/v)/dx = (u'v - uv') / v² ..................... Quotient Rule
dy/dx = [(6x²)(x²) - (2x³ - 1)(2x)] / (x²)²
dy/dx = [6x⁴ - (4x⁴ - 2x)] / x⁴
dy/dx = (6x⁴ - 4x⁴ + 2x) / x⁴
dy/dx = (2x⁴ + 2x) / x⁴
dy/dx = (2x⁴ / x⁴) + (2x / x⁴)
dy/dx = 2 + 2xˉ³
dy/dx = 2 + (2 / x³)
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u = 2x³ - 1
u' = 6x²
v = x²
v' = 2x
d(u/v)/dx = (u'v - uv') / v² ..................... Quotient Rule
dy/dx = [(6x²)(x²) - (2x³ - 1)(2x)] / (x²)²
dy/dx = [6x⁴ - (4x⁴ - 2x)] / x⁴
dy/dx = (6x⁴ - 4x⁴ + 2x) / x⁴
dy/dx = (2x⁴ + 2x) / x⁴
dy/dx = (2x⁴ / x⁴) + (2x / x⁴)
dy/dx = 2 + 2xˉ³
dy/dx = 2 + (2 / x³)
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