How do you find, and what are, the number of complex roots, the possible number of real roots, and the possible rational roots of the following equation:
3x^2 + 11x - 10 = 0
3x^2 + 11x - 10 = 0
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x = -11 ± √((11)^2 - 4(3)(-10) / 2(3)
x = -11 ± √(121 + 120) / 6
x = -11 ± √(241) / 6
241 = prime, so that can't be simplified.
Therefore it has two real roots and they are...
x = (-11 + √241) / 6
x = (-11 - √241) / 6
x = -11 ± √(121 + 120) / 6
x = -11 ± √(241) / 6
241 = prime, so that can't be simplified.
Therefore it has two real roots and they are...
x = (-11 + √241) / 6
x = (-11 - √241) / 6