Roots of an equation
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Roots of an equation

[From: ] [author: ] [Date: 13-02-26] [Hit: ]
the possible number of real roots,241 = prime, so that cant be simplified.Therefore it has two real roots and they are.........
How do you find, and what are, the number of complex roots, the possible number of real roots, and the possible rational roots of the following equation:

3x^2 + 11x - 10 = 0

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x = -11 ± √((11)^2 - 4(3)(-10) / 2(3)

x = -11 ± √(121 + 120) / 6

x = -11 ± √(241) / 6

241 = prime, so that can't be simplified.

Therefore it has two real roots and they are...

x = (-11 + √241) / 6
x = (-11 - √241) / 6
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