(Hint Balance equation) Zn(s) + HCL(aq) --> ZnCl2 (aq) + H2(g)
Please explain
Please explain
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The atomic mass of Zn is 65.4 g/mol so you have 5/65.4 = 0.0765 moles of Zn; from the equation, it takes the same no of moles of HCl to react with the Zn, so you need 0.0765 moles of HCl. moles = concentraion x volume 0.0765 = 5.0*V; V= 0.0153 L so you need 15 mL