The captain of a baseball team assigns himself to the 4th place in batting order. In how many ways can he assign the remaining places to his 8 teammates, if just 3 men are considered eligible for 1st position?
I'm lost w/ my father also! What a kind of a hard question permutation! :(
I'm lost w/ my father also! What a kind of a hard question permutation! :(
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8 players
position 1: 3 possibilities
position 2: 7 possibilities
position 3: 6
position 5: 5
position 6: 4
position 7: 3
position 8: 2
position 9: 1
multiply them together... 15120
if you didn't restrict the lead off spot it would be 40320
position 1: 3 possibilities
position 2: 7 possibilities
position 3: 6
position 5: 5
position 6: 4
position 7: 3
position 8: 2
position 9: 1
multiply them together... 15120
if you didn't restrict the lead off spot it would be 40320