It is determined by immersing a crown in water that is volume is 26 in^3 =0.015 ft^3. (a) What would its weight be if it were made of pure gold? (b) What would its weight be if half of its volume was gold and half lead?
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26 cubic inches is 426 cubic centimeters to one extra significant digit.
Gold has a density of 19.31 g/cm³
D = m / V
m = D x V = 19.31 g/cm³ x 426 cm³ = 8226 g or 8200 g to the two significant digits that you are allowed for this answer
If half the volume is lead, then ...
m = 19.31 g/cm³ x 213 cm³ + 11.34 g/cm³ x 213 cm³ = 6528 g or 6500 g to two significant digits.
Gold has a density of 19.31 g/cm³
D = m / V
m = D x V = 19.31 g/cm³ x 426 cm³ = 8226 g or 8200 g to the two significant digits that you are allowed for this answer
If half the volume is lead, then ...
m = 19.31 g/cm³ x 213 cm³ + 11.34 g/cm³ x 213 cm³ = 6528 g or 6500 g to two significant digits.