Evaluate the limit?!
Favorites|Homepage
Subscriptions | sitemap
HOME > > Evaluate the limit?!

Evaluate the limit?!

[From: ] [author: ] [Date: 13-02-24] [Hit: ]
So your final answer is -5. I will assume you understand what that answers means. If you dont, just let me know.......
Evaluate the limit: lim x---> -2
x^2-x-6/x+2


This is one of my review questions for my test, having a hard time understanding limits, could someone solve and explain please??

-
Hi Chelsea,
There are a few ways to approach this problem. I am going to approach it the way I believe your instructor would like to see it.

Your first approach would be simply plugging the number in, but you soon realize that it is undefined. At a second glance you notice that the numerator can be factored. You can get that to (x-3)(x+2). Now you have

Limit as x approaches -2
[ (x-3) (x+2) ] / (x+2)

You can cancel out the (x+2)'s leading to the limit as x approaches -2
(x-3)

You can now simply plug in the -2, (-2 - 3) = -5.

So your final answer is -5. I will assume you understand what that answers means. If you don't, just let me know.

-
Let L = limit

L = (x^2 - x - 6) / (x+2)

L = (x+2)(x-3) / (x+2) = x-3

L = -5 as x approaches -2
1
keywords: limit,the,Evaluate,Evaluate the limit?!
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .