Find the volume, in ml, when 7.00 gr of O2 and 1.5 gr of CI2 are mixed in a container with a (MORE IS BELOVE )

pressure of 48.2 atm and at a temp of 22 °C

first of ol i wanna say thanks to u for giving me a BA :)

mass of o2=7 gram
mass of cl2=1.5 gram
molecular mass of o2=2*16
molecular mass of cl2=2*35.5
n(o2)=mass/molecular mass
=7/32

n(cl2)=1.5/72

total no of moles =n(o2)+n(cl2)
find it

T=22+273=295


PV = n x R x T

u have n ,R ,T and P
just put the value and get ur answer :)






R= 8.314 mol^-1

n=no of moles

i m not a tchr :P
i m in the same class as u r in:P

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