How would you solve the expression:
(1-sin^2x)/(sinx-cscx)
A) -cosx
B)-sinx
C)sin^2x
D) cos^2x
If someone could show me all steps of the work I'd really appreciate it. I've been trying to do this for a half hour and I can't get it.
(1-sin^2x)/(sinx-cscx)
A) -cosx
B)-sinx
C)sin^2x
D) cos^2x
If someone could show me all steps of the work I'd really appreciate it. I've been trying to do this for a half hour and I can't get it.
-
(1-sin^2(x))/(sinx-cscx)
(cos^2(x))/(sin^2(x)/sinx-1/sinx)
(cos^2(x))/((sin^2(x)-1)/sinx)
sinxcos^2(x)/-(-sin^2(x)+1)
sinxcos^2(x)/(-cos^2(x))
-sinx
B)
(cos^2(x))/(sin^2(x)/sinx-1/sinx)
(cos^2(x))/((sin^2(x)-1)/sinx)
sinxcos^2(x)/-(-sin^2(x)+1)
sinxcos^2(x)/(-cos^2(x))
-sinx
B)
-
good job trying so long!
i'll try to help:
first things i see is we can go cos^2x/(sinx-1/sinx)
then combine the 2 parts in the denominator and get
cos^2x/((sin^2x-1)/sinx)
cos^2x/(cos^2x/sinx)
sinx
did i miss a sign somewheres?
i'll try to help:
first things i see is we can go cos^2x/(sinx-1/sinx)
then combine the 2 parts in the denominator and get
cos^2x/((sin^2x-1)/sinx)
cos^2x/(cos^2x/sinx)
sinx
did i miss a sign somewheres?