Question about cardinalities
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Question about cardinalities

[From: ] [author: ] [Date: 12-11-19] [Hit: ]
These can be seen pretty quickly by thinking about what elements you can have.(or just look at it from a combinatorial point of view).Thus, |A x P(B)| = 5*4=20.......
Let A = {a, b, c, d, e} and B = {0, 1}.

|A × (P) B| =

|P(A) ×P( B)| =

I need to learn the answers for these two?

is the first 2 * 2^2?

I think the second one is 2^5 * 2^2

not sure about the first.

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The order of a power set of any set C is 2^n where n=card(C).

|C x D| for C,D sets is m*n where n=card(C), and m=card(D).

These can be seen pretty quickly by thinking about what elements you can have. (or just look at it from a combinatorial point of view).

Thus, |A x P(B)| = 5*4=20.
|P(A) x P(B)| = 2^5*2^2 = 2^7 = 128
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