Determine the vector function r(y) whose graph is the cross-section of the graph of:
z=f(x,y) = 2x^2 - 4y^2 + 2x - y; by the plane x = 2
How would I solve this problem? I have a test next week, please help!!
z=f(x,y) = 2x^2 - 4y^2 + 2x - y; by the plane x = 2
How would I solve this problem? I have a test next week, please help!!
-
Given:
z = f(x,y) = 2x² - 4y² + 2x - y
At x = 2
z(y) = 8 - 4y² + 4 - y
z(y) = -4y² - y + 12
r(y,z) = (y² + z²)^(1/2)
let z = -4y² - y + 12
r(y) = (y² + {-4y² - y + 12}²)^(1/2)
I will leave it in this form but feel free to multiply it out, if you like.
z = f(x,y) = 2x² - 4y² + 2x - y
At x = 2
z(y) = 8 - 4y² + 4 - y
z(y) = -4y² - y + 12
r(y,z) = (y² + z²)^(1/2)
let z = -4y² - y + 12
r(y) = (y² + {-4y² - y + 12}²)^(1/2)
I will leave it in this form but feel free to multiply it out, if you like.