1) n=3. I know this one is 18 electrons
I'm confused on these parts
2)n=4, l=1
3)n=6 l=1 m(l)=-1
I'm confused on these parts
2)n=4, l=1
3)n=6 l=1 m(l)=-1
-
hello again ....
2) n = 4 , l = 1
direct method ...l = 1 is p subshell and as there are 3 orbitals and every orbital can have 2 electrons ....so 6 electrons possible ...
another method ....find the 4 quantum numbers for each electron ...
you know that for every l = 1 ....ml = -l to +l ...so possible values for ml = -1 , 0 , +1
and for every ml value two ms value =+1/2 ,-1/2 ....so
for ml = -1 ...ms = +1/2, -1/2
ml = 0 , ms = +1/2,-1/2
ml = +1 , ms = +1/2,-1/2
so all in all there are 6 electrons ....
3) n = 6 , l = 1 , ml = -1
so ms = -1/2,+1/2
so 2 electrons
feel free to ask any question
2) n = 4 , l = 1
direct method ...l = 1 is p subshell and as there are 3 orbitals and every orbital can have 2 electrons ....so 6 electrons possible ...
another method ....find the 4 quantum numbers for each electron ...
you know that for every l = 1 ....ml = -l to +l ...so possible values for ml = -1 , 0 , +1
and for every ml value two ms value =+1/2 ,-1/2 ....so
for ml = -1 ...ms = +1/2, -1/2
ml = 0 , ms = +1/2,-1/2
ml = +1 , ms = +1/2,-1/2
so all in all there are 6 electrons ....
3) n = 6 , l = 1 , ml = -1
so ms = -1/2,+1/2
so 2 electrons
feel free to ask any question