How would I describe the symmetry for g(x) = x^3 - 5

[From: ] [author: ] [Date: 12-07-09] [Hit: ]

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g(x) = x^3 - 5

dg/dx = 3x^2 = 0

x = 0

g(0) = 0^3 - 5v= -5

the symmetry for g(x) is y = -5

1

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