The tickets for a high school basket ball game are $3.00 for students and $4.50 for adults. At Tuesday night's game, 112 tickets were sold for a total of $399.00. How many student tickets were sold?
68
40
42
70
68
40
42
70
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students= S
adults= A
S+ A = 112.00 | x4.50| --> (4.50)S+(4.50)A= 504.00
(3.00)S+(4.50)A = 399.00 | x1 | --> (3.00)S+(4.50)A = 399.00
--------------------------------------… - (subtract)
1.50S = 105.00
S = 105/1.50 = 70
adults= A
S+ A = 112.00 | x4.50| --> (4.50)S+(4.50)A= 504.00
(3.00)S+(4.50)A = 399.00 | x1 | --> (3.00)S+(4.50)A = 399.00
--------------------------------------… - (subtract)
1.50S = 105.00
S = 105/1.50 = 70
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let A be the number of adult tickets, and S be the number of student tickets.
112 total tickets are the sum of student and adult tickets:
112 = A+S
The money earned is equal to the student price times the number of students and the adult price by the number of adults:
399 = 4.5A+3S
Let's solve the first equation for A and then substitute that for A in the second equation:
A = 112-S
399 = 4.5(112-S) +3S
So now we can expand that and we get:
399 = 504 -4.5S+3S
399-504 = -4.5S+3S
-105 = -1.5S
And we get our answer:
-105/-1.5 = S
S = 70
112 total tickets are the sum of student and adult tickets:
112 = A+S
The money earned is equal to the student price times the number of students and the adult price by the number of adults:
399 = 4.5A+3S
Let's solve the first equation for A and then substitute that for A in the second equation:
A = 112-S
399 = 4.5(112-S) +3S
So now we can expand that and we get:
399 = 504 -4.5S+3S
399-504 = -4.5S+3S
-105 = -1.5S
And we get our answer:
-105/-1.5 = S
S = 70
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of student tickets sold= x
# of adult tickets sold= y
x + y = 112 , you can make this y = 112 - x
3x + 4.5y = 399
now you have a system of equations that you can solve by substituting the y value (112-x) into the second equation and solve from there.
# of adult tickets sold= y
x + y = 112 , you can make this y = 112 - x
3x + 4.5y = 399
now you have a system of equations that you can solve by substituting the y value (112-x) into the second equation and solve from there.
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A. 112 - 68 = 44, 68 x $3.00 = $204, 44 x $4.50 = $198, $204 + $198 = $402 **not your answer**
B. 112 - 40 = 72, 40 x $3.00 = $120, 72 x $4.50 = $324, $120 + $324 = $444 **not your answer**
C. 112 - 42 = 70, 42 x $3.00 = $126, 70 x $4.50 = $315, $126 + $315 = $441 **not your answer**
D. 112 - 70 = 42, 70 x $3.00 = $210, 42 x $4.50 = $189, $210 + $189 = $399 **ANSWER**
B. 112 - 40 = 72, 40 x $3.00 = $120, 72 x $4.50 = $324, $120 + $324 = $444 **not your answer**
C. 112 - 42 = 70, 42 x $3.00 = $126, 70 x $4.50 = $315, $126 + $315 = $441 **not your answer**
D. 112 - 70 = 42, 70 x $3.00 = $210, 42 x $4.50 = $189, $210 + $189 = $399 **ANSWER**
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You have 4 answers. 1st try 68students x 3 = then add the remaining 44 adult tickets at 4.50 to find out if it totals 399.00 so (68x3)+44x4.50= does it equal 399.00 if not try (40x3)+72x4.50=?? Keep going till you get an answer that equals 399.00.
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Let the amount of student tickets sold be x
3x + 4.5 ( 112 - x) = 399
3x + 504- 4.5x = 399
1.5x = 105
x = 70 ANSWER
3x + 4.5 ( 112 - x) = 399
3x + 504- 4.5x = 399
1.5x = 105
x = 70 ANSWER
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s=# of student tickets a=# of adult tickets
s+a=112
3s+4.5a=399
those are the equations. now figure the rest yourself. I am not gonna do your homework for you.
s+a=112
3s+4.5a=399
those are the equations. now figure the rest yourself. I am not gonna do your homework for you.