How many solutions does the following system of equations have?
y=(5)/(2)*x+2
2y=5x+4
A. Infinitely many
B. Two
C. One
D. Zero
y=(5)/(2)*x+2
2y=5x+4
A. Infinitely many
B. Two
C. One
D. Zero
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the two are identical so infinitely many.
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y = (5)/(2)*x + 2 ........................ [1]
2y = 5x + 4 .......................... [2]
From [1], 2y = 5/x + 4 .................. [3]
From [2] and [3], 5x +4 = 5/x +4,
5x^2 = 5, ===> x^2 = 1,
x = 1, and x = -1 >======================< ANSWER
AND
Answer is : B. Two .===================< ANSWER
2y = 5x + 4 .......................... [2]
From [1], 2y = 5/x + 4 .................. [3]
From [2] and [3], 5x +4 = 5/x +4,
5x^2 = 5, ===> x^2 = 1,
x = 1, and x = -1 >======================< ANSWER
AND
Answer is : B. Two .===================< ANSWER