Lim x-->(pi/2)− sec x / tan x
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Lim x-->(pi/2)− sec x / tan x

[From: ] [author: ] [Date: 12-07-01] [Hit: ]
......
how would you solve this. it cant be solved by L'hospital's rule

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lim{x→π/2} [1/cos(x)] / [sin(x)/cos(x)]
= lim{x→π/2} csc(x) = 1

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lim_{x→π/2} sec(x)/tan(x)
= lim_{x→π/2} (1/cos(x)) / (sin(x)/cos(x))
= lim_{x→π/2} cos(x) / (cos(x)sin(x))
= lim_{x→π/2} 1/sin(x)
= 1
1
keywords: minus,Lim,pi,sec,tan,gt,Lim x-->(pi/2)− sec x / tan x
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