All I know is that all four sides are 1cm in length.
Also of course the intersection of the two diagonals will be a right angle.
Is it possible for me to find the length of the diagonals with just this information?
Thanks for your help :)
Also of course the intersection of the two diagonals will be a right angle.
Is it possible for me to find the length of the diagonals with just this information?
Thanks for your help :)
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You need more info. See the diagram.
I have provided 2 different quadrilaterals with length of all sides = 1. By definition both are rhombus's
All rhombus's have perpendicular right angles.
So I have provided 2 rhombus's that meet the above criteria with very different diagonal lengths.
Then it is not possible to deduce the lengths of the diagonals other than to say the must be less than 2 and greater than 0
I hope this helps
I have provided 2 different quadrilaterals with length of all sides = 1. By definition both are rhombus's
All rhombus's have perpendicular right angles.
So I have provided 2 rhombus's that meet the above criteria with very different diagonal lengths.
Then it is not possible to deduce the lengths of the diagonals other than to say the must be less than 2 and greater than 0
I hope this helps
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This is one another question that would help YOU:
How do i find the diagonals of a rhombus?
If the sides of a rhombus are all 4 inches long, and one diagonal is 4 inches long, what is the length of the other diagonal?
Answer:
Think of the rhombus as two equilateral triangles which share a side. Now take one of those equilateral triangles and split in half to form two 30-60-90 triangles. The short leg of the 30-60-90 triangle has a length of 2 inches (half of 4 inches). The long leg, therefore, measures 2sqrt(3) inches. The long diagonal is made of two of these long legs, so it's twice as long: 4sqrt(3) inches.
OR
The diagonals of a rhombus always intersect at a right angle, so you can use the Pythagorean theorem on the right triangle created from two half-diagonals, and one of the sides of the rhombus.
SO, YOU CANNOT FIND without knowing at least ONE OF LENGTH OF DIAGONALS.
How do i find the diagonals of a rhombus?
If the sides of a rhombus are all 4 inches long, and one diagonal is 4 inches long, what is the length of the other diagonal?
Answer:
Think of the rhombus as two equilateral triangles which share a side. Now take one of those equilateral triangles and split in half to form two 30-60-90 triangles. The short leg of the 30-60-90 triangle has a length of 2 inches (half of 4 inches). The long leg, therefore, measures 2sqrt(3) inches. The long diagonal is made of two of these long legs, so it's twice as long: 4sqrt(3) inches.
OR
The diagonals of a rhombus always intersect at a right angle, so you can use the Pythagorean theorem on the right triangle created from two half-diagonals, and one of the sides of the rhombus.
SO, YOU CANNOT FIND without knowing at least ONE OF LENGTH OF DIAGONALS.
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take 1 triangle and use ratio of 30°, 60°, 90° triangle, the given value 1 is the hypotenuse:
a o b should not be greater than 1 nor less than 0 or a negative value.
the sum of a and b should be greater than 1 to create a triangle.
.
relation of sides:
a=b sqrt 3, b=c/2 and c=2b
.
given: c=1
.
b=c/2 ==> b=1/2 o 0.5 cm
.
a=b sqrt 3 ==> a=(1/2)*sqrt 3
a=(sqrt 3)/2 or 0.8660254 cm
.
the shortest diagonal:
sd=2b
sd=2*(1/2) ==> sd=1 cm answer (@_@)
.
the longest diagonal:
ld=2a
ld=2*(sqrt 3)/2
ld=sqrt 3 or 1.7320508 cm answer (@_@)
.
all the given side is hypotenuse:
check by pythagorean:
[(sqrt 3)/2]^ plus (1/2)^2=1^2
sqrt [3/4 plus 1/4]=1
sqrt (4/4)=1
2/2=1
1=1
.
(a plus b) > c
0.5 plus 0.8660254 > 1
1.3660254 > 1
.
hope this helps (@_@)
a o b should not be greater than 1 nor less than 0 or a negative value.
the sum of a and b should be greater than 1 to create a triangle.
.
relation of sides:
a=b sqrt 3, b=c/2 and c=2b
.
given: c=1
.
b=c/2 ==> b=1/2 o 0.5 cm
.
a=b sqrt 3 ==> a=(1/2)*sqrt 3
a=(sqrt 3)/2 or 0.8660254 cm
.
the shortest diagonal:
sd=2b
sd=2*(1/2) ==> sd=1 cm answer (@_@)
.
the longest diagonal:
ld=2a
ld=2*(sqrt 3)/2
ld=sqrt 3 or 1.7320508 cm answer (@_@)
.
all the given side is hypotenuse:
check by pythagorean:
[(sqrt 3)/2]^ plus (1/2)^2=1^2
sqrt [3/4 plus 1/4]=1
sqrt (4/4)=1
2/2=1
1=1
.
(a plus b) > c
0.5 plus 0.8660254 > 1
1.3660254 > 1
.
hope this helps (@_@)
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You should use the pythagorean theorem to find 1/2 of a diagonal. 1^2+1^2=c^2. Dont have a good calculator on me (doing this mobile) but all you need to do is find the square root of two. Then because thats only half a diagonal you multiply it by two.