Calc 2 area between curves help

Find the area of the region enclosed between y=4sin(x) and y=2cos(x) from x=0 to x=0.7/pi.

Now I can see that it is broken into two regions. I just can't seem to find the middle point to break it off at. like 0 to X + X to .7/pi

y1 = y2 ---> tan x = 1 / 2----> sin x = 1 / √5 , cos x = 2 /√5

thus int over x in [ 0 , arctan .5] of { y2 - y1 } + int over [ arctan .5 , 0.7π] of { y1 - y2 ]