I was given a question with two right angle triangles in it. The question is to evaluate the unknown values for x,y, a and delta for the right angle triangles.
Triangle 1:
A right angle triangle, the length of the opposite is 70cm. I was given a 53 degree angle which is in between hypotenuse and opposite. The 'x' is at the hypotenuse and 'y' is at adjacent.
Triangle 2:
A right angle triangle, the length of the hypotenuse is 110mm and the length of the opposite is 40mm. The 'a' is at the adjacent. The delta is between the adjacent and hypotenuse.
I hope you can understand. Thanks.
Triangle 1:
A right angle triangle, the length of the opposite is 70cm. I was given a 53 degree angle which is in between hypotenuse and opposite. The 'x' is at the hypotenuse and 'y' is at adjacent.
Triangle 2:
A right angle triangle, the length of the hypotenuse is 110mm and the length of the opposite is 40mm. The 'a' is at the adjacent. The delta is between the adjacent and hypotenuse.
I hope you can understand. Thanks.
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1)
90 - 53 = 37
70 / sin(37) = x / sin(90)
70 / sin(37) = x / 1
x = 70 / sin(37)
x = 116.3148099
x ~ 116 cm
y
= sqrt((116.3148099)^2 - 70^2)
= sqrt(8629.134997)
= 92.89313751
~ 93 cm
2)
a
= sqrt(110^2 - 40^2)
= sqrt(10500)
= 102.4695077 mm
~ 102 mm
sin(delta) = opposite / hypotenuse
sin(delta) = 40 / 110
delta = 21.32368626 degrees
delta ~ 21 degrees
90 - 53 = 37
70 / sin(37) = x / sin(90)
70 / sin(37) = x / 1
x = 70 / sin(37)
x = 116.3148099
x ~ 116 cm
y
= sqrt((116.3148099)^2 - 70^2)
= sqrt(8629.134997)
= 92.89313751
~ 93 cm
2)
a
= sqrt(110^2 - 40^2)
= sqrt(10500)
= 102.4695077 mm
~ 102 mm
sin(delta) = opposite / hypotenuse
sin(delta) = 40 / 110
delta = 21.32368626 degrees
delta ~ 21 degrees