Grade 10 Quadratics? 10 points! Exam Tomorrow Morning!
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Grade 10 Quadratics? 10 points! Exam Tomorrow Morning!

[From: ] [author: ] [Date: 12-06-22] [Hit: ]
5, 20.how do you find 5 ordered pairs? and what info do i use to graph the relation?2. What is the equation of the new parabola if the graph of y=x*2 is translated 3 units to the left?......
* = power of
(please answer asap, my exams tomorrow!) even if you have part of one question thats great too
1. The equation is y=(x-3)*2 - 16
I found ..
the zeros: (x+3) (x-6)
axis of symmetry: -1.5
and vertex: -1.5, 20.25)
how do you find 5 ordered pairs? and what info do i use to graph the relation?

2. What is the equation of the new parabola if the graph of y=x*2 is translated 3 units to the left?

3. If the parabola shown only gives me the vertex is (4,0) how do you find the equation? (points up)

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you messed up #1
y = (x - 3)² - 16 ∙ ∙ ∙ ∙ ∙ ∙ ∙ ∙ ∙ ∙ ∙ this is a difference of squares, so
y = [(x - 3) + 4] [(x - 3) - 4] ∙ ∙ ∙and then simplify
y = (x + 1)(x - 7)
so zeros at -1 and 7, axis of symmetry x = (-1+7)/2 = 6/2 = 3
zeros are axis of symmetry ±4, so vertex is 4² down at (3, -16)
5 pairs? go 1 and 2 left and right of vertex, chanting 1 over, 1² up, 2 over, 2² up,
which gives you (1,-12), (2,-15), (3,-16), (4,-15), (5,-12)

by the way, standard notation for exponents is ^, so 3^2 = 9.

y = x^2 translated 3 left is y = (x + 3)^2

think of all parabolas as having 2 zeros, so if there's just 1, the 2 are the same,
which gives you y = (x - 4)²
depending on the vertical stretch you might make it y = a(x - 4)²
1
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