the letter happens are written on identical pieces of paper and placed in an envelope. Each situation below is a separate, new scenario. They do bot relate to each other.
A single piece of paper is removed, observed, and then replaced. A second piece of paper is removed and observed. What is the probability that at least one piece of paper has an P on it?
A single piece of paper is removed. IT is not an P, this paper is not replaced into the envelope. A second piece of paper is removed. What is the probability that paper is an P?
can you please explain your reasoning, using high-school methods.
Thank You All
A single piece of paper is removed, observed, and then replaced. A second piece of paper is removed and observed. What is the probability that at least one piece of paper has an P on it?
A single piece of paper is removed. IT is not an P, this paper is not replaced into the envelope. A second piece of paper is removed. What is the probability that paper is an P?
can you please explain your reasoning, using high-school methods.
Thank You All
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You have to figure the probability of each letter being drawn.
h = 1/7
a = 1/7
p = 2/7
e = 1/7
n = 1/7
s = 1/7
======
P = 1
The chances of getting a p the first time is 2/7 and the probability of getting a p the second time is 2/7 as well because the original piece of paper was replaced.
4/14 = 2/7
In the second scenario, the paper was not a p and was not returned, raising to the probability of getting a p to 2/6, which is 1/3. A complete third of the papers have a p on them.
ANSWER
a) 2/7
b) 1/3
h = 1/7
a = 1/7
p = 2/7
e = 1/7
n = 1/7
s = 1/7
======
P = 1
The chances of getting a p the first time is 2/7 and the probability of getting a p the second time is 2/7 as well because the original piece of paper was replaced.
4/14 = 2/7
In the second scenario, the paper was not a p and was not returned, raising to the probability of getting a p to 2/6, which is 1/3. A complete third of the papers have a p on them.
ANSWER
a) 2/7
b) 1/3