What is the solution of log (3) x – log (3) 2 = 2

* number 3 is the base
SO here is how I've been trying to solve it:
Its subtracting so I would divide and eliminate log 3: x/2=2 then I multiply two in both sides which equals to 4 but thats wrong. Pls help :/

Solution: First we must always remember that logarithms are exponents, therefore we have the following,

log3 (x) - log3 (2) = 2

log3 ( x / 2 ) = 2

3^2 = ( x / 2 )

9 (2) = x

x = 18

For additional assistance, please see also:

Rules of Logarithms:

http://en.wikipedia.org/wiki/Logarithm
http://www.sosmath.com/algebra/logs/log4…
http://www.purplemath.com/modules/logrul…
http://www.mathwords.com/l/logarithm_rul…
http://hyperphysics.phy-astr.gsu.edu/hba…
http://oakroadsystem.com/math/loglaws.ht…
http://www.andrews.edu/~calkins/math/web…

log (3) x – log (3) 2 = 2
log(3) (x/2) = 2
x/2 = 3^2
x = 18

idk