Integrate x[sin^5(x^2)](cosx^2) dx
Do you apply one of the trig transformations using the identity cos^2(x)+sin^2(x) = 1?
If so, how?
I tried typing the problem at wolfram and it says that computation has timed out... :(
Do you apply one of the trig transformations using the identity cos^2(x)+sin^2(x) = 1?
If so, how?
I tried typing the problem at wolfram and it says that computation has timed out... :(
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Hello,
let's wrtie the integral as:
∫ sin⁵(x²) x cos(x²) dx =
let:
sin(x²) = u
(differentiating both sides)
d[sin(x²)] = du
2x cos(x²) dx = du
x cos(x²) dx = (1/2) du
then, substituting:
∫ sin⁵(x²) x cos(x²) dx = ∫ u⁵ (1/2) du =
(pulling the constant out)
(1/2) ∫ u⁵ du =
(1/2) [1/(5+1)] u^(5+1) + C =
(1/2)(1/6)u⁶ + C =
(1/12)u⁶ + C =
let's substitute back sin(x²) for u, ending with:
(1/12)sin⁶(x²) + C
I hope it helps
let's wrtie the integral as:
∫ sin⁵(x²) x cos(x²) dx =
let:
sin(x²) = u
(differentiating both sides)
d[sin(x²)] = du
2x cos(x²) dx = du
x cos(x²) dx = (1/2) du
then, substituting:
∫ sin⁵(x²) x cos(x²) dx = ∫ u⁵ (1/2) du =
(pulling the constant out)
(1/2) ∫ u⁵ du =
(1/2) [1/(5+1)] u^(5+1) + C =
(1/2)(1/6)u⁶ + C =
(1/12)u⁶ + C =
let's substitute back sin(x²) for u, ending with:
(1/12)sin⁶(x²) + C
I hope it helps