Can somebody please help me out, math problem

The first 5 terms of the geometric sequence a[n]=-6a[n-1], a[1]=-3 for n ≥ 2

A. a[1]=3, a[2]=18, a[3]=108, a[4]=648, a[5]=3888
B. a[1]= -3, a[2]=18, a[3]=108, a[4]=648, a[5]=3888
C. a[1]= -3, a[2]= -18, a[3]= -108, a[4]= -648, a[5]= -3888
D. a[1]= -3, a[2]=18, a[3]= -108, a[4]=648, a[5]= -3888

a[1] = -3
a[2] = -6a[1] = -6(-3) = 18
a[3] = -6a[2] = -6(18) = -108
a[4] = -6a[3] = -6(-108) = 648
a[5] = -6a[4] = -6(648) = -3888

Hence, the answer is D. a[1] = -3, a[2] =18, a[3] = -108, a[4] = 648, a[5] = -3888