Can you please help me solve 2x^2 + 4x - 6 = 0 using the null theorem, steps included.
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2x^2 + 4x - 6 = 0
( 2x - 2 ) ( x + 3 ) = 0
( 2x - 2 ) = 0 ; ( x + 3 ) = 0
( 2x - 2 ) = 0
2x - 2 = 0
2x = 2
2x / 2 = 2 / 2
x = 1
( x + 3 ) = 0
x + 3 = 0
x = - 3
Solutions :
x = 1, - 3
Checking :
( 2x - 2 ) ( x + 3 ) = 0
2x^2 + 6x - 2x - 6 = 0
2x^2 + 4x - 6 = 0
My Answer :
x = 1, - 3
( 2x - 2 ) ( x + 3 ) = 0
( 2x - 2 ) = 0 ; ( x + 3 ) = 0
( 2x - 2 ) = 0
2x - 2 = 0
2x = 2
2x / 2 = 2 / 2
x = 1
( x + 3 ) = 0
x + 3 = 0
x = - 3
Solutions :
x = 1, - 3
Checking :
( 2x - 2 ) ( x + 3 ) = 0
2x^2 + 6x - 2x - 6 = 0
2x^2 + 4x - 6 = 0
My Answer :
x = 1, - 3
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Please define null theorem here. I do not see it online