Rate of change question SUPREME CHALLENGE!
Favorites|Homepage
Subscriptions | sitemap
HOME > > Rate of change question SUPREME CHALLENGE!

Rate of change question SUPREME CHALLENGE!

[From: ] [author: ] [Date: 12-06-01] [Hit: ]
= 1.3 * 100 / 2 = 65 m^3.......
A value is slowly opened in a pipeline such that the volume flow rate R varies with time according to the relation R = kt (t>0).

Calculate the total volume of water that flows through the value in the first 10 seconds if k=1.3 m^3s^-2


******
Just some thought This question has me so confused
this is is a cylindrical shape so v=pi(r^2)h
dv/dt = kt = r
so... ktdx = (k/2)t^2 + C
My other thought was that N=N<0> e^kt
but somehow dn/dt becomes Kt

-
I would take the integral of R dt from t= 0 to t = 10;

integral (R dt) = integral (kt dt) = k*t^2 / 2 evaluated from t= 0 to t = 10

= 1.3 * 100 / 2 = 65 m^3.
1
keywords: change,CHALLENGE,question,SUPREME,of,Rate,Rate of change question SUPREME CHALLENGE!
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .