TENPOINTS： show work and answer these algebriac expressions

y+3(y-6)=2(3-y)=3y
and
3(n-2)+12=(6n-3(4-N))

no need explaining, thanks very much :) please show work!

1.
y+3(y-6) = 2(3-y) + 3y,
y +3y -18 = 6 -2y +3y,
4y +2y -3y = 6 +18,
3y = 24,

y = 24/3 = 8 >========================< ANSWER

2.
3(n-2)+12=(6n-3(4-n)),
3n -6 +12 = 6n -12 +3n,
3n -6n -3n = -12 -12 +6,
-6n = -18,

n = 18/6 = 3 >========================< ANSWER

im not sure what you are trying to ask with the first one.. maybe an error?

but the second one:
3(n-2)+12=6n-3(4-n) ... im assuming you had caps lock on
3n-6+12=6n-12+3n ........ distribute the 3(n-2) and -3(4-n)
3n+6=9n-12 ......... combine like terms and add 12 to both sides
3n+18=9n ..........subtract 3n from both sides
18=6n ........... divide 6 to both sides
3=n

1).
y + 3(y - 6) = 2(3 - y) + 3y
4y - 18 = y + 6
3y = 24
y = 8

2).
3(n - 2) + 12 = (6n - 3(4 - n))
3n + 6 = 9n - 12
6n = 18
n = 3

y+3(y-6)=2(3-y)-3y

y+3y-18=6-2y-3y
9y=24
y=8/3
and
3(n-2)+12=(6n-3(4-N))

3n-6+12=6n-12+3n
n=3