A 1.5 X 10^3 kg vehicle accelerates from rest to a velocity of 15.0 m/s in 6.00 s. Determine the output of power in the car in this 6.00 s.
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At the end of the 6s, the car has kinetic energy KE = 1*2 m*V^2
= 750*15^2 = 168,750J
Power = Energy per unit time = 168,750/6 = 28,125J/s = 28,125 Watts = 28.125kW
Another way to calculate this is
F = ma
a = [Vf-Vi]/[t2-t1] = 15/6 = 2.5m/s^2
F = 1500*2.5 = 3750N
Solve for d = 1/2 *a*t^2 = 1.25*36 = 45m
Now use Work = F*d = 3750*45 = 168,750J
168,750/6 = 28, 125W same answer
= 750*15^2 = 168,750J
Power = Energy per unit time = 168,750/6 = 28,125J/s = 28,125 Watts = 28.125kW
Another way to calculate this is
F = ma
a = [Vf-Vi]/[t2-t1] = 15/6 = 2.5m/s^2
F = 1500*2.5 = 3750N
Solve for d = 1/2 *a*t^2 = 1.25*36 = 45m
Now use Work = F*d = 3750*45 = 168,750J
168,750/6 = 28, 125W same answer
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KE = 0.5 MV^2
KE = 0.5 * 1.5 * 10^3 kg * (15 )^2m/s
KE = 168,750 J
Pwr = KE/Time = 168,750 J / 6 s = 28,125 J/s = 28,125 W
KE = 0.5 * 1.5 * 10^3 kg * (15 )^2m/s
KE = 168,750 J
Pwr = KE/Time = 168,750 J / 6 s = 28,125 J/s = 28,125 W
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I Dont no sorry i tryed to figure it out but then i searched and found it answered on Enotes.com just copy and past that formula on google and it should pop up with the link to the Answer Good Luck!
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Never mind. It looks like the other guy got it fine.