Math help please!!!!

Can you help me solve these problems. Also, could you show your work, too? Thanks.

21. Solve. {1 / (3x+9) } - { 2 / (x+3) } = 2
22. Solve 8/x + 15/x^2 = -1
29. Simplify. { ( x / (x-4) ) + ( 6 / (x+4) ) } / { 3 / (2x^2 - 32) } ... I hope this one isn't too confusing.

Please answer quick, and you don't have to answer them all, unless you want to. Thanks ahead of time!

21) get a common denominator
[(x+3) / (3x+9)(x+3)] - [ 2(3x+9) / (3x+9)(x+3)] = 2
combine fractions and expand brackets
(-5x-15) / (3x^2 + 18x +27) = 2
multiply by (3x^2 + 18x +27)
-5x-15=6x^2 + 36x + 54
6x^2 + 41x +69
(23 + 6x)(3 + x)
x=-3.83 or x= -3

22) times whole thing by x^2 to get:
8x + 15 = -x^2

rearrange to get

x^2 + 8x + 15

factorise
(x+5)(x+3)

x= -5 or x=-3

1) 1/(3x+9)-2(x+3)=2
1*(x+3)/{3x+9)(x+3)}-2*(3x+9)/{(3x+9)(…
(x+3-6x-18)/{(3x+9)(x+3)}=2
(-5x-15)/{(3x-9)(x+3)}=2
-5x-15=2*(x+3)(3x+9)=2*(3x^2+18x+27)=6…
0=6x^2+41x+42

(-41+-sqrt(41^2-4*6*42))/(2*6)
(-41+-sqrt(1681-1008))/12
-41/12 + or - 673^.5/12

x=-66.942, -15.058

2) 8/x+15/x^2=-1
8x/x^2+15/x^2=-1
(8x+15)/x^2=-1
8x+15=-x^2
x^2+8x+15=0
(x+3)(x+5)=0

x=-3,-5

3) {x/(x-4)+6/(x+4)}/{3/(2x^2-32)}
Breaking this down to avoid confusion:
Numerator- x/(x-4)+6/(x+4)
x(x+4)/{(x-4)(x+4)}+6(x-4)/{(x+4)(x-4)…
(x^2+4+6x-24)/{(x+4)(x-4)}
(x^2+6x-20)/(x^2-16)
Denominator
3/(2x^2-32)
3/{2(x^2-16)}
Okay divide by denominator by flipping it over and multipling.
(x^2+6x-20)/(x^2-16)*2(x^2-16)/3
2(x^2-6x-20)/3

2/3*x^2-4x-40/3